Proving Convergence and Hausdorffness in the Finite Complement Topology on R

  • Thread starter Ka Yan
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In summary, the conversation is discussing the behavior of a sequence xn = 1/n in the finite complement topology on R, denoted by FCTR. It is proved that R with FCT is not a Hausdorff space, and it is also shown that xn converges to every point of R. The person is asking for confirmation on their reasoning.
  • #1
Ka Yan
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Is my reasoning correct?

Original problem:
In the finite completement topology on R(denoted by FCTR here), to what point or poionts does the sequense xn = 1/n converge?

I firstly prove that R with FCT does not a Hausdorff.

Let Tf be FCTR, x1, x2 are two arbitrary points of R, U1, U2 are their neighborhoods, respectively.

Then R with Tf is not a Hausdorff, since:
U1, U2 are open in R, U1, U2[tex]\in[/tex]Tf. R-U1 is finite, and R-U2 is finite. Then if U1[tex]\cap[/tex]U2=[tex]\phi[/tex] (which is necessary for a Hausdorff space), then R-(U1[tex]\cap[/tex]U2) will be R. Whereas R-(U1[tex]\cap[/tex]U2) = (R-U1)[tex]\cup[/tex](R-U2), which is finite, by definition, and impossible to be R. Hence U1 and U2 are not disjoint. Thus R with FCT does not a Hausdorff.

Secondly I prove xn converge to every point of R.

Since for every x in R with FCT, the neighborhood of x is the set Ux=R-{xn}. And for every Ux, all xn are in Ux, thus xn converge to x. For the arbitrary of x, xn converge to every point of R.

Thx!
 
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  • #2
Could someone kind enough to tell me, please?
 

1. What is the Finite Complement Topology on R?

The Finite Complement Topology on R is a topology on the set of real numbers R, where the open sets are defined as the complements of finite subsets of R. In other words, a set U is open if and only if its complement R\U is finite.

2. Why is it called the Finite Complement Topology?

This topology is called the Finite Complement Topology because the open sets are defined by the finite subsets of the set R. This means that the open sets are finite, while the closed sets can be infinite.

3. How do you prove convergence in the Finite Complement Topology on R?

In the Finite Complement Topology on R, a sequence of points converges to a point x if and only if x is a limit point of the sequence. This means that every open set containing x must also contain infinitely many points from the sequence. To prove convergence, you can show that for any open set U containing x, there exists a point from the sequence in U.

4. What is the definition of Hausdorffness?

Hausdorffness is a property of a topological space where any two distinct points can be separated by disjoint open sets. In other words, for any two points x and y in the space, there exist open sets U and V such that x is in U, y is in V, and U and V do not overlap.

5. Is the Finite Complement Topology on R a Hausdorff space?

No, the Finite Complement Topology on R is not a Hausdorff space. This is because any two non-empty open sets in this topology must have a non-empty intersection, which violates the definition of Hausdorffness. In fact, this topology is an example of a non-Hausdorff space.

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