1. The problem statement, all variables and given/known data Two Positive charges q1 = q2= 2.0 microC are located at x=0, y = .30 m and x =0, y =-.30m. Third point charge Q =4.0 microC is located at x=.40 m, y = 0. What is the net force magnitude and the direction on charge q1 exerted by the other two charges. 2. Relevant equations coulomb's law 3. The attempt at a solution Ok, so this is what I did. I drew the charges and then for the point charge Q acting on q1, i drew out the components and everything. So, first I just solved for the F(Q on q1)=k(Qq1)/(.50^2). I found the .50 through the pythagorean theorem. So I get .29 N. Then for the components. I solved that by having the x component be negative since cos is negative in the second quadrant and y component is positive since sin is positive in the second quadrant. I got the respective values to be -.17 and .23. Then I did F(q2 on q1). There is no x component and there is only a y component. The y component through coulomb's law, comes out to -.1 since they both are positive and so they repel. So, the Fx is -.17 and Fy is .23-.1 which is .13 N. I found the resultant to be .21 and theta to be 37 degrees. However, this is not the right answer. Any thing that I am doing wrong??Or am i not even following the steps correctly..I would appreciate any help. Thanks..