Point Charges creating an electric field

[squib]

A point charge q =-4.00 nC is at the point x = 0.600 m, y = 0.800 m, and a second point charge q=6nC is at the point x = 0.600 m, y = 0.

A)Calculate the magnitude of the net electric field at the origin due to these two point charges.

I assume i can just treat the electric field charge as a vector pointed towards the - charge from the origion, using E = (1/4*pi*E_0)(q/r^2).
The other charge is therefore a horizontal vector on the x-axis pointing inwards.
After adding components together, I came to:
(8.988*10^9)(16.97108653*10^-9), any idea where I went wrong?

Next.
B)What is the direction of the net electric field at the origin due to these two point charges.
I assume I would just use the same technique here, and ended up with 169.1314747 degrees up from the x-axis... any ideas on where I'm messing up?

 

[squib]

nm was stupid and messed up my vectors

 

[quicknote]

I would like to clarify a few things about your calculations. Firstly, the formula you have used for electric field is correct, but it is important to note that the electric field is a vector quantity and therefore, both magnitude and direction need to be considered in calculations.

For part A, the net electric field at the origin can be calculated by adding the individual electric fields due to each point charge. The magnitude of the net electric field can be calculated using the formula you mentioned, but it should be noted that the distance (r) in the formula is the distance from the point charge to the point of interest, in this case, the origin (0,0). So, the distance for the first point charge would be 0.800 m and for the second point charge, it would be 0.600 m. After calculating the individual electric fields, you can add them using vector addition to get the net electric field at the origin.

For part B, the direction of the net electric field can be calculated using the direction of the individual electric fields and vector addition. It is important to note that the direction of the electric field is always in the direction of the force on a positive test charge. So, for the first point charge, the direction would be towards the origin (as it is a negative charge) and for the second point charge, it would be away from the origin (as it is a positive charge). After adding the two vectors, you can use trigonometry to find the direction of the net electric field.

I hope this helps clarify any confusion and helps you in solving the problem accurately. Remember to always double-check your calculations and take into account the vector nature of electric fields.