1. The problem statement, all variables and given/known data A positive point charge Q1 = 1.9 x 10^-5C is fixed at the origin of coordinates, and aa negative charge Q2 = -6.5 x 10^-6C is fixed to the axis at x = +2.0m. Find the location of the place(s) along the x axis where the electric field due to these two charges is zero. IF there is only one location then enter zero for the second location. x = ______m x = ______m 3. The attempt at a solution for the distance I used Q1 = x and Q2 = abs val of 2-x and then used the equation of Q1/r1^2 = Q2/r2^2 so I started out with :::: first (1.9 x 10^-5C)/x^2 = (-6.5 x 10^-6C)/((2-x)^2) then (1.9 x 10^-5C)/x^2 = (-6.5 x 10^-6C)/(x^2-4x+4) then multiplied both denominators to get rid of them and got::: (1.9 x 10^-5C)(x^2-4x+4) = (-6.5 x 10^-6C)(x^2) then multiplied them all out and got::: (2.55 x 10^-5C)(x2) - (7.6 x 10^-5)(x) + ((7.6 x 10^-5) = 0 at this point I used the quadratic formula and used::: a = 2.55 x 10^-5 b = 7.5 x 10^-5 c = 7.5 x 10^-5 Now...here is the problem. When I plug these all in to the quadratic formula I end up with a negative number in the square root which you cant take the square root of... any help is appreciated...anybody to show me where I went wrong is appreciated as well!