Poisson Distribution question

  • Thread starter tiger2380
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  • #1
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Can someone help me with this question:
If X has a Poisson distribution so that 3P(X=1)=P(X=2)
find the pdf of X, and P(X=4)????
 

Answers and Replies

  • #2
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"pdf," I assume means Poisson Distribution Function.

Well, the function is [tex]P(n)=\frac{e^{-\kappa}\kappa^n}{n!}[/tex]

So since we know values of n, the important thing is to find the particular value of the constant [tex]kappa, \kappa[/tex]
 
Last edited:
  • #3
mathman
Science Advisor
7,870
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It looks like k=6.
 

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