# Poisson Distribution question

Can someone help me with this question:
If X has a Poisson distribution so that 3P(X=1)=P(X=2)
find the pdf of X, and P(X=4)????

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"pdf," I assume means Poisson Distribution Function.

Well, the function is $$P(n)=\frac{e^{-\kappa}\kappa^n}{n!}$$

So since we know values of n, the important thing is to find the particular value of the constant $$kappa, \kappa$$

Last edited:
mathman