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Poisson Distribution question

  1. Apr 29, 2007 #1
    Can someone help me with this question:
    If X has a Poisson distribution so that 3P(X=1)=P(X=2)
    find the pdf of X, and P(X=4)????
  2. jcsd
  3. Apr 29, 2007 #2
    "pdf," I assume means Poisson Distribution Function.

    Well, the function is [tex]P(n)=\frac{e^{-\kappa}\kappa^n}{n!}[/tex]

    So since we know values of n, the important thing is to find the particular value of the constant [tex]kappa, \kappa[/tex]
    Last edited: Apr 29, 2007
  4. Apr 30, 2007 #3


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    It looks like k=6.
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