- #1
semidevil
- 157
- 2
ok, so on average, there is a chromosome mutation link once every 10,000 baby births.
approximate the probability that exactly 3 of the next 20,000 babies born will have the mutation.
so using poisson distribution, I let
p = 1/10,000
n = 20,000.
and use formula (e^(-np) * (np)^k / k!
so when I do the calculation, do I sum it all up for k = 1, 2, 3, or do I just calculate k = 3 and that is my final answer?
if they ask at most 3, then I would sum up k = 1, 2, 3 right?
I first applied the formula for k = 1, 2, 3, but then it got me thinking about it...
approximate the probability that exactly 3 of the next 20,000 babies born will have the mutation.
so using poisson distribution, I let
p = 1/10,000
n = 20,000.
and use formula (e^(-np) * (np)^k / k!
so when I do the calculation, do I sum it all up for k = 1, 2, 3, or do I just calculate k = 3 and that is my final answer?
if they ask at most 3, then I would sum up k = 1, 2, 3 right?
I first applied the formula for k = 1, 2, 3, but then it got me thinking about it...