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Poisson / mean / sd

  1. Apr 6, 2005 #1

    Mo

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    I am attempting a past paper question from school, i dont have the answer (and it doesnt look like i will anytime soon!)

    The question:
    "The Random variable X has a poisson distribution with mean 4. The random variable Y is defined by

    Y = 4X + 1

    Find the mean and standard deviation of Y"

    So .. where do i begin?

    I understand that the mean and variance of a poisson distribution is lambda.I know that the square root of the variance is the SD.They are telling us that this R.V X has a mean and variance of 4 right?

    Am i right in thinking that the mean of Y is the same as the mean of (4X + 1)?

    So is this right .. (at least to start with)?

    E(4X + 1) = 4

    or is it ...

    4E(X) + 1 where E(X) is 4?


    Help is very much appreciated!

    Regards,
    Mo

    PS: Stats is not something that i understand all that easy :frown:
     
  2. jcsd
  3. Apr 6, 2005 #2
    The 2nd : E(4X+1)=4*E(X)+1...and then i think it's like :

    var(Y)=E(Y^2)-E(Y)^2=E(16X^2+8X+1)-(4*E(X)+1)^2=16(E(X^2)-E(X)^2)=16*var(X)...but I'm not sure
     
  4. Apr 6, 2005 #3

    mathman

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    Science Advisor
    Gold Member

    Note to Kleinwolf: The variance calculation is correct. In general, adding a constant leaves the variance unchanged, while multiplying by a constant changes the variance by multiplying by the constant squared.
     
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