The children in a small town own slingshots. In a recent contest 4% of them were such poor shots that they did not hit the target even once in 100 shots. If the number of times a randomly selected child has hit the target is approximately a Poisson random variable, determine the percentage of children who have hit the target at least twice. Just want to make sure my reasoning/logic for this is correct... so P(X=x) = e-λλn /n! so from the question P(X=0) = 0.04 = e-λ => λ = 3.21887 Then P(X >= 2) = 1 - ( P(X=0) + P(X=1) ) = 1 - 0.04 - e-3.218873.218871/1! I get 0.83 does this seem reasonable?