- #1

saravanan_n

- 12

- 0

dA=A(1-m dL/L)^2 -A

where

A=Area of cross section

L=length

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- Thread starter saravanan_n
- Start date

- #1

saravanan_n

- 12

- 0

dA=A(1-m dL/L)^2 -A

where

A=Area of cross section

L=length

- #2

marlon

- 3,777

- 11

saravanan_n said:

dA=A(1-m dL/L)^2 -A

where

A=Area of cross section

L=length

Whithin what context did you acquire this equation ?

marlon

- #3

EnumaElish

Science Advisor

Homework Helper

- 2,327

- 124

What is m?

Looks to me it's a formula for calculating the % change in cross-sectional area for a % stretch lengthwise. Cross-section area is a function of the width (or perhaps width x length). But width is compressed as length is stretcehd and that has to be taken into account while calculating the change in area.

Having written all this, I don't get why a squared term is involved, because while the calculation of an area may involve a square, the change in such an area would be linear.

From a Yahoo search on "Poisson's ratio":

http://www.millersv.edu/~jdooley/macro/derive/elas1/poissn/poissn.htm [Broken]

Looks to me it's a formula for calculating the % change in cross-sectional area for a % stretch lengthwise. Cross-section area is a function of the width (or perhaps width x length). But width is compressed as length is stretcehd and that has to be taken into account while calculating the change in area.

Having written all this, I don't get why a squared term is involved, because while the calculation of an area may involve a square, the change in such an area would be linear.

From a Yahoo search on "Poisson's ratio":

http://www.millersv.edu/~jdooley/macro/derive/elas1/poissn/poissn.htm [Broken]

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