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- Thread starter th3plan
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Does this help?

[tex]= \int_{a}^{b} \sqrt { [x'(t)]^2 + [y'(t)]^2 }\, dt.[/tex]

5 cos(t) - cos(5t) and 5 sin(t)- sin(5t) will no doubt fall within an area between [itex]x\pi \theta[/itex] and [itex]x\pi\theta[/itex] do you know how to work that out? Or how to work out appropriate ranges for cos and sin?

Personally I'd chose something like between 0 and [itex]\pi[/itex]... or 0 and [itex]2\pi[/itex]

[tex]= \int_{a}^{b} \sqrt { [x'(t)]^2 + [y'(t)]^2 }\, dt.[/tex]

5 cos(t) - cos(5t) and 5 sin(t)- sin(5t) will no doubt fall within an area between [itex]x\pi \theta[/itex] and [itex]x\pi\theta[/itex] do you know how to work that out? Or how to work out appropriate ranges for cos and sin?

Personally I'd chose something like between 0 and [itex]\pi[/itex]... or 0 and [itex]2\pi[/itex]

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- #3

HallsofIvy

Science Advisor

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Those parametric equations do NOT give a conic section.

You can, however, cover the figure by letting t go from 0 to [itex]2\pi[/itex]

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how do i mathematically find the right interval to evaulate it ?

- #5

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how do i mathematically find the right interval to evaulate it ?

Which range will your shape fall in?

It's between the range of 0 and 360 degrees (or a full circle) right? In that case what is the range/interval in degrees to radians? Couldn't be 0 to 2[itex]\pi[/itex] could it?

[tex]\text{radians}=\text{degrees}\times\frac{\pi\;\text{radians}}{180}[/tex]

[tex]\text{degrees}=\text{radians}\times\frac{180}{\pi\;\text{radians}}[/tex]

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