1. The problem statement, all variables and given/known data Find the area inside the lemniscate r = 2sqrt(sin(2theta)) 2. Relevant equations Integral from a to b of (1/2)[f(theta)]^2 d(theta) 3. The attempt at a solution I tried integrating from 0 to 2pi and got an area of 0. Then I tried integrating from 0 to pi and still got an area of 0. I looked at the answer and they integrated from 0 to pi/2 and then multiplied the integral by 2. I don't understand why they chose to integrate from 0 to pi/2 or why they multiplied the integral by 2? Any help would be greatly appreciated.