1. The question The position of a particle is given by r(t) = acos(wt) i + bsin(wt) j. Assume a and b are both positive and a > b. The plane polar coordinates of a particle at a time t equal to 1/8 of the time period T will be given by _ 2. Relevant equations r(t) = acos(wt) i + bsin(wt) j. 3. The attempt at a solution at t = T/8 the value of wt=π/4. therefore in Cartesian coordinates the vector is r= a/√2 + b/√2. so in polar coordinates this transforms to r = √(a2 + b2)/2 and tanθ = b/a. My answer does not match with the given one. Also if we were to write the polar equation of the curve how would that follow ?