Find the area of the region which is inside the polar curve [tex] r =5*cos(\theta)[/tex](adsbygoogle = window.adsbygoogle || []).push({});

and outside the curve [tex] r = 3-1*cos(\theta)[/tex]

when i plugged those two functions into my calculator and found the bounds from 1.0471976 to 5.2359878.

my integral:

[tex] \int_{1.0471976}^{5.2359878} 1/2*(5*cos(\theta))^2 - 1/2*(3-1*cos)^2[/tex]

and got a final answer of

-4.10911954 which is incorrect. anyone know what i did wrong?

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# Homework Help: Polar curve

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