# Polar form to Cartesian form

1. Jan 29, 2008

### chonghuh

1. The problem statement, all variables and given/known data

I solved this following problem but I am not sure whether I did this right: convert
(1/(2^j)) to cartesian form.
2. Relevant equations

3. The attempt at a solution

re^j$$\theta$$ = a+jb

a=r cos $$\theta$$= cos -$$\pi$$/2
b= sin -$$\pi$$/2 = -1

1/(2^j) = 2^-j
=2^e^(-pi j /2)
=2^-j

Last edited: Jan 29, 2008
2. Jan 29, 2008

### Dick

1/2^j=2^(-j) as you said. But to get to the e form use 2=e^ln(2).

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