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Find the polar form of the equation 6x^2 + 3xy + 6y^2 = -3

I have run this 4 separate times and have come up with 4 different answers.

PLEASE HELP!

r^2= 6 over -6 - 3sin(theta)cos(theta)

r^2=-3 over 6 - 3sin(theta)cos(theta)

r^2=9 over 6 + 3sin(theta)cos(theta)

r^2=-3 over 6 + 3sin(theta)cos(theta)