1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Polar graph area

  1. Feb 1, 2013 #1
    Question is attached:


    [tex] r^2 = a^2 + 6acos(\theta) + 9cos^2(\theta) [/tex]

    using [tex] \frac{1}{2}\displaystyle\int^{2\pi}_0 r^2d\theta [/tex]

    using this I get a = 7

    are my limits right, as it says theta can't be 2pi?

    Attached Files:

  2. jcsd
  3. Feb 1, 2013 #2


    User Avatar
    Science Advisor
    Homework Helper

    a=7 looks ok. It doesn't really matter if they write the limit as <2pi or <=2pi. Including or excluding a single point doesn't change the integral.
    Last edited: Feb 1, 2013
  4. Feb 1, 2013 #3
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook