Polar Graphing

  • Thread starter Ashford
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  • #1
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Homework Statement


Find the Maximum and Minimum of the following equation.
r=2-2cos([tex]\Theta[/tex])


The Attempt at a Solution


Max- 2-2 cos (0[tex]\pi[/tex])=0
(0,0[tex]\pi[/tex]);(0,2[tex]\pi[/tex])

Min 2-2cos([tex]\pi[/tex])=4
(4,[tex]\pi[/tex])

Do i just have these backwards?
 

Answers and Replies

  • #2
Dick
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0<4, so yes, you have them backwards. 4 is the max, 0 is the min.
 
  • #3
HallsofIvy
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I'm wondering how you determined that
Max- 2-2 cos (0)=0
(0,0[itex]\pi[/itex\);(0,2[itex]\pi[/itex])

Min 2-2cos()=4
(4,[itex]\pi[/itex])

And, by the way, an equation does not have a max or min- a function does. An equation does not even have a "value" to be max or min.
 

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