# Polar Graphing

## Homework Statement

Find the Maximum and Minimum of the following equation.
r=2-2cos($$\Theta$$)

## The Attempt at a Solution

Max- 2-2 cos (0$$\pi$$)=0
(0,0$$\pi$$);(0,2$$\pi$$)

Min 2-2cos($$\pi$$)=4
(4,$$\pi$$)

Do i just have these backwards?

Dick
Homework Helper
0<4, so yes, you have them backwards. 4 is the max, 0 is the min.

HallsofIvy
Homework Helper
I'm wondering how you determined that
Max- 2-2 cos (0)=0
(0,0$\pi[/itex\);(0,2[itex]\pi$)

Min 2-2cos()=4
(4,$\pi$)

And, by the way, an equation does not have a max or min- a function does. An equation does not even have a "value" to be max or min.