# Homework Help: Polar Integral Question

1. Oct 23, 2005

### bigedd1227

I'm not sure if I'm doing this conversion correctly. I have to convert the following double integral into polar. The integration part I can do, I just want to make sure I converted correctly. And sorry about the formatting bc I don't kno how to do the math formatting.

Int(Int((x^2+y^2))dy)dx
the bounds on the outer integral are -1 to 1
the bounds on the inner integral are -sqrt(1-y^2) to sqrt (1-y^2)

now here is what I got converting it to polar

Int(Int(r^3)dr)dtheta
outer bounds = 0 to 2pi
inner bounds = 0 to 1

Did I do the conversion correctly?
Thanks for the help

2. Oct 24, 2005

### Galileo

Lookin' good, but in the first integral the bounds on the inner integral should be -sqrt(1-x^2) to sqrt (1-x^2).

Last edited: Oct 24, 2005