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## Homework Statement

Convert 2cis(-pi/3)cis(pi/6) into cartesian form. Show all working to obtain full marks

## Homework Equations

I know that the equation for it is 2((cos(theta) +isin(theta))+(cos(theta)+isin(theta)))

## The Attempt at a Solution

Okay so cos of (-p/3) = 1/2

Sin of (-p/3) = sqrt(3)/2

Cos(pi/6)=sqrt(3)/2

Sin(pi/6) = 1/2

So basically you get this big answer as 2((1/2-isqrt(3)/2)+(sort(3)/2+1/2i))

Is this the correct answer or do I need to multiply it out?

I know the R for this is 2. I know the theta is tan^-1(y/x) but I am a little confused...