Convert 2cis(-pi/3)cis(pi/6) into cartesian form. Show all working to obtain full marks
I know that the equation for it is 2((cos(theta) +isin(theta))+(cos(theta)+isin(theta)))
The Attempt at a Solution
Okay so cos of (-p/3) = 1/2
Sin of (-p/3) = sqrt(3)/2
Sin(pi/6) = 1/2
So basically you get this big answer as 2((1/2-isqrt(3)/2)+(sort(3)/2+1/2i))
Is this the correct answer or do I need to multiply it out?
I know the R for this is 2. I know the theta is tan^-1(y/x) but I am a little confused...