Polar To Cartesian

1. Sep 15, 2005

chap

I'm back studying after a couple of years out and have become a little rusty. currently learning about the J operator.

I have no problem converting Cartesian to Polar, but struggle to convert Polar to Cartesian. Some basic examples and a step by step guide would be appreciated.

2. Sep 15, 2005

Tom Mattson

Staff Emeritus
Given $(r,\theta )$ you can get $(x,y)$ by the following procedure:

$x=r\cos(\theta)$
$y=r\sin(\theta)$

3. Sep 15, 2005

chap

Simple now you've pointed it out.

Thanks, that helps a lot.

4. Sep 16, 2005

amcavoy

Easier than cartesian to polar, huh?

5. Sep 16, 2005

Tom Mattson

Staff Emeritus
I know, I was thinking the same thing. :rofl: