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Polar To Cartesian

  1. Sep 15, 2005 #1
    I'm back studying after a couple of years out and have become a little rusty. currently learning about the J operator.

    I have no problem converting Cartesian to Polar, but struggle to convert Polar to Cartesian. Some basic examples and a step by step guide would be appreciated.


    Thank you in advance.
     
  2. jcsd
  3. Sep 15, 2005 #2

    Tom Mattson

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    Given [itex](r,\theta )[/itex] you can get [itex](x,y)[/itex] by the following procedure:

    [itex]x=r\cos(\theta)[/itex]
    [itex]y=r\sin(\theta)[/itex]
     
  4. Sep 15, 2005 #3
    Simple now you've pointed it out.

    Thanks, that helps a lot.
     
  5. Sep 16, 2005 #4
    Easier than cartesian to polar, huh?
     
  6. Sep 16, 2005 #5

    Tom Mattson

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    I know, I was thinking the same thing. :rofl:
     
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