Polar To Cartesian

  • Thread starter chap
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  • #1
chap
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I'm back studying after a couple of years out and have become a little rusty. currently learning about the J operator.

I have no problem converting Cartesian to Polar, but struggle to convert Polar to Cartesian. Some basic examples and a step by step guide would be appreciated.


Thank you in advance.
 

Answers and Replies

  • #2
quantumdude
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Given [itex](r,\theta )[/itex] you can get [itex](x,y)[/itex] by the following procedure:

[itex]x=r\cos(\theta)[/itex]
[itex]y=r\sin(\theta)[/itex]
 
  • #3
chap
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Simple now you've pointed it out.

Thanks, that helps a lot.
 
  • #4
amcavoy
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chap said:
Simple now you've pointed it out.

Thanks, that helps a lot.

Easier than cartesian to polar, huh?
 
  • #5
quantumdude
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I know, I was thinking the same thing. :rofl:
 

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