1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

POlarisation and intensity

  1. Jul 22, 2011 #1
    Hi,


    1. The problem statement, all variables and given/known data

    I have the following question:

    I found two formulas given for the intensity after polarised light went through a polarisation filter.
    2. Relevant equations

    [tex] I_{1}=I_{0}*\frac 1 2 [/tex]

    and

    [tex] I_{1}= I_{0}*cos^{2}(\phi)[/tex]



    3. The attempt at a solution
    Well I don't know when to use which equation. Does it depend on the filter used or does it depend on the angle?
    Thanks for your help

    edit:

    I think when the axis of the filter is parallel to the incoming rays its just 1/2 and when theres an angle between the incoming rays and the filter I have to use the one with cosine.
     
    Last edited: Jul 22, 2011
  2. jcsd
  3. Jul 22, 2011 #2
    The first one is used when the light is natural light;
    And use the second when it is linearly polarized light.
     
  4. Jul 22, 2011 #3

    berkeman

    User Avatar

    Staff: Mentor

    As IDOG says, the first equation is for unpolarized light incident on the polarizer, and the 2nd is for polarized light with its axis of polarization at an angle phi to the polarizer's axis.

    You can use the 2nd equation to derive the first equation, BTW. What is the average value of cos^2(phi) ?
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: POlarisation and intensity
  1. Polarisation of light (Replies: 2)

  2. Polarisation of light (Replies: 2)

Loading...