Two polarizers are oriented at 38.8o to each other and plane-polarized light is incident on them. If only 14.6 percent of the light gets through both of them, what was the initial polarization direction of the incident light?(adsbygoogle = window.adsbygoogle || []).push({});

Ok, I'm not exactly sure what this problem is asking for, do they want an angle or what?

So basically the only equation given for this section is I = Io*cos^2 theta.

I did ((cos*38.8)^2)((cos*38.8)^2) = .369....

I don't see how I can solve the problem with just this, I thought maybe I can relate it to Snell's eq., but there is no index (n) given.

Also I know that I-final = 14.6% = .146, but once again I don't really know what to do with this.

Any hints and help will be greatly appreciated.

Thanks....

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# Homework Help: Polarization I = Io*cos^2 theta

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