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Two polarizers are oriented at 38.8o to each other and plane-polarized light is incident on them. If only 14.6 percent of the light gets through both of them, what was the initial polarization direction of the incident light?

Ok, I'm not exactly sure what this problem is asking for, do they want an angle or what?

So basically the only equation given for this section is I = Io*cos^2 theta.

I did ((cos*38.8)^2)((cos*38.8)^2) = .369....

I don't see how I can solve the problem with just this, I thought maybe I can relate it to Snell's eq., but there is no index (n) given.

Also I know that I-final = 14.6% = .146, but once again I don't really know what to do with this.

Any hints and help will be greatly appreciated.

Thanks....

Ok, I'm not exactly sure what this problem is asking for, do they want an angle or what?

So basically the only equation given for this section is I = Io*cos^2 theta.

I did ((cos*38.8)^2)((cos*38.8)^2) = .369....

I don't see how I can solve the problem with just this, I thought maybe I can relate it to Snell's eq., but there is no index (n) given.

Also I know that I-final = 14.6% = .146, but once again I don't really know what to do with this.

Any hints and help will be greatly appreciated.

Thanks....

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