Solve Polarized Sphere Field: Find Charges & Calculate Field

In summary, the conversation discusses a homework problem involving a sphere with radius R carrying a uniform polarization in the radial direction. The goal is to find the bound charges and calculate the field they produce outside the sphere. After some calculations, the result is E = kR2/(ε0r2), but this seems to contradict the fact that a polarization should not create a field outside the sphere. The discrepancy is attributed to the mathematics behind ∇\bulletk/r2 = 0 and the presence of a delta function. It is also noted that there is no field inside the sphere due to the lack of charges. The conversation ends with a discussion about the nature of the polarization being uniform and whether the answer is actually incorrect.
  • #1
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Homework Statement


A sphere with radius R carries a uniform polarization in the radial direction P = k/r2
Find the bound charges and calculate the field they produce outside the sphere.

Homework Equations


ρ = -∇[itex]\bullet[/itex]P
σ = P[itex]\bullet[/itex][itex]\hat{r}[/itex]

The Attempt at a Solution


We find σ = k/r2
ρ = 0
So the field they produce is E = kR2/(ε0r2)

But this can't be true! How can a polarization create a field outside the sphere? Something is definitely wrong. Because we also have:
D = ε0E
And using a Gaussian surface you find:
E=0

And I am confident in the last result. There is something disappearing in the above - where have all the charges of opposite sign gone? I believe it has to do with the mathematics behind ∇[itex]\bullet[/itex]k/r2 = 0. For that the pesky delta function is involved in that I believe. If ρ=0 we also find no field inside the sphere. Can that really be true?
 
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  • #2
Let me check a couple of things: The polarisation is k/r2 in the radial direction, so how is it uniform polarisation? Also, I agree with your answer E = kR2/(ε0r2) due to the bound charges. Why do you think it is wrong?
 

1. What is a polarized sphere field?

A polarized sphere field is a type of electric field created by a charged sphere. It is characterized by a varying electric field strength at different points in space, with the strongest field being at the surface of the charged sphere.

2. How do you find the charges in a polarized sphere field?

To find the charges in a polarized sphere field, you can use Gauss's law which states that the electric flux through a closed surface is equal to the net charge enclosed by the surface. By calculating the electric flux at different points on the surface of the sphere, you can determine the magnitude and sign of the charges present.

3. What is the process for calculating the field in a polarized sphere field?

To calculate the field in a polarized sphere field, you can use Coulomb's law which states that the electric field at a point in space is equal to the force between two charges divided by the distance between them squared. By considering the charges present in the sphere and their distance from the point, you can calculate the electric field strength at that point.

4. How is a polarized sphere field different from a uniform electric field?

A polarized sphere field is different from a uniform electric field in that it is not constant throughout space. In a uniform electric field, the field strength and direction are the same at all points, while in a polarized sphere field, the field strength and direction vary depending on the distance from the charged sphere.

5. Can a polarized sphere field exist in a vacuum?

Yes, a polarized sphere field can exist in a vacuum. In fact, it is commonly used in vacuum technology for applications such as ion traps and particle accelerators. The absence of air molecules in a vacuum does not affect the electric field created by a charged sphere.

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