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Poles of laplace transform

  1. Jul 14, 2009 #1
    if i said that x(t) is real,
    why X(s) must occur in conjugate reciprocal pairs ?
  2. jcsd
  3. Jul 16, 2009 #2


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    It does not.
    If [tex]x(t) = e^{at}[/tex], then [tex]X(s) = \frac{1}{s-a}[/tex], wich has a real pole at s = a.
    In the other way, if x(t) is a sinusoid, then X(s) will have complex conjugate poles.
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