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~christina~

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**[SOLVED] police car siren (waves)**

## Homework Statement

A police car speeds toward a warehouse door with its siren emitting sinusoidal waves of frequency fs = 300 Hz, intending to crash through the door. The car moves at 30 m / s and the ambient temperature is 35º C.

(a) What is the wavelength of the wave if the siren is stationary?

(b) Find the wavelengths of the waves in front of and behind the source when the siren is moving at 30 m / s.

(c) What frequency does the driver of the police car hear reflected from the warehouse?

(d) Does the driver detect a beat frequency? If yes, then find the beat frequency; if no, explain why not.

## Homework Equations

[tex]v= (331m/s) \sqrt{1 + Tc/ 273} [/tex]

[tex] \lambda = v/f [/tex]

[tex] \lambda' = \lambda \pm vs/f [/tex]

[tex] f '= (v/(v-vs))f [/tex]

## The Attempt at a Solution

**a) wavelength if the siren is stationary**

temp = [tex] 35 ^oC [/tex]

f= 300Hz

[tex]v= (331m/s) \sqrt{1 + Tc/ 273} [/tex]

[tex]v= (331m/s) \sqrt{1 + 35 ^oC [/tex]/ [tex] 273 ^oC [/tex]

v= 351.578m/s

[tex] \lambda = v/f [/tex]

[tex] \lambda[/tex] = 351.578m/s / 300Hz = 1.172m

**b) find the wavelengths of the waves in front of and behind the source if the siren is moving at 30m/s**

Not sure if this is the right equation for what they are asking but I used it for both in front of and behind the source wavelengths => [tex] \lambda' = \lambda \pm vs/f [/tex]

ALSO NOT SURE IF LAMBDA (without ') is the wavelength I found in part a) but I used it....could be incorrect but I don't see where I'd get lambda if I didn't use that one for lambda in equation.

front of car wavelength:

[tex] \lambda'_{front} = \lambda \pm vs/f [/tex]

[tex] \lambda'_{front} = 1.172m - (30m/s)/ 300Hz = 1.072m[/tex]

back of car wavelength:

[tex] \lambda'_{back} = \lambda \pm vs/f [/tex]

[tex] \lambda'_{back} = 1.172m + (30m/s)/ 300Hz = 1.272m [/tex]

**c) frequency that the driver of the police car hears reflected from the wareheouse**

I looked it up and I think that the frequency of the reflected wave is the same of the wave that hits it thus...(not sure though)

[tex] f '= (v/(v-vs))f [/tex]

v= velocity of sound in air = 351.578m/s (35 deg celcius)

f= 300Hz

vs= 30m/s

[tex] f '= [(351.578m/s)/ (351.578m/s -30m/s)]*(300Hz) = 327.9869 Hz [/tex]

**d) does the driver detect a beat frequency? Yes then find the beat frequency if no explain why not.**

I'm not even sure what that is however I tried looking online and found that a beat frequency is made up of more than one wave and also each wave has different frequencies...thus I think that since the police car siren has one frequency and the reflected wave has the same frequency I think and so my conclusion would be there is no beat frequency

IS this right?

(I saw an example however where a police car(stationary) had a radar wave which was directed toward a moving vehicle and the reflected waves created a beat frequency but this is the opposite in my case with the police car moving and instead of a stationary vehicle there is a wall Thus I'm really not sure now)

Can someone help me out?

THANKS

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