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Police Chasing Speeding Car

  1. Sep 24, 2006 #1
    Hey. I need help on this question. A walkthrough would be great. Thanks in advance!
    A speeder passes a parked police car at 38.0 m/s. The police car starts from rest with a uniform acceleration of 2.29 m/s^2.
    a) How much time passes before the speeder is overtaken by policeman? b) How far does the speeder get before being overtaken by the police car?
  2. jcsd
  3. Sep 24, 2006 #2


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    In order to overtake the speeder, to which displacement must the displacement of the police car be equal to? Which are the equations of diaplacement for the police car, and which ones are for the speeder?
  4. Sep 24, 2006 #3
    confused... to which formulas are you referring, radou?
    if anyone else has any input, please help...THANK YOU!
  5. Sep 24, 2006 #4
    You can find the basic accleration/velocity equations here.


    Hint: start out by figuring out how long it will take the accelerating police car to achieve the same velocity (38ms) as the speeding car. Use this as T1. There will be a T2, it will be the time it takes the police car to travel the remaining distance to the speeder.
    Last edited: Sep 24, 2006
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