Police Question..... Question: A speeder passes a parked police car at 30.0 m/s. The police car starts from rest with a uniform acceleration of 2.44 m/s^2. a) How much time passes before the speeder is overtaken my the police car? Ans: 24.6 s b) How far does the speeder get before being overtaken by the police car? Ans: 738 m My Questions/Work: To the best of my knowledge, we know the following..... Cop Vi: 0.0 m/s Cop Accel: 2.44 m/s2 Spdr V: 30 m/s a) Formula: Vf = Vi + AT ???? What should I use as the Cop's Final Velocity?