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Polynomial of degree 7

  1. Sep 19, 2008 #1
    can anyone tell me the solution of- x2=k2-k2x7/2
     
  2. jcsd
  3. Sep 20, 2008 #2

    HallsofIvy

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    (Is that first "-" a minus or a hyphen?)

    If you let y= x1/2, x2= k2- k2x7/2 becomes y4= k2- k2y7 or k2y7+ y4- k2= 0. I see no simple way to factor that and, in general, solutions to polynomial equations of degree higher than 4 cannot be written in terms of algebraic functions.
     
  4. Sep 20, 2008 #3
    i got that far as well. isn't there a formula for sum of product of roots n at a time, n-1 at a time and so on?
     
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