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Polynomials math homework

  1. Sep 25, 2006 #1
    What are the ROots:


    ok the 13 really causes a problem because you can't factor that.
    So I move the right side to the left and then you can't find a number that fits so that it equals zero so I tried factoring it somehow but can't do it can someone help?
  2. jcsd
  3. Sep 25, 2006 #2
    That's a fairly evil problem to give you, but oh well (if I needed to solve it, I'd just throw it into maple and not think about it!).

    It's written that way for a reason. Factor the left side and rearrange to change it to

    [tex]x^2(x^2 + 4x + 14) + (4x + 13) = 0.[/tex]

    Do you see how to factor it now?
  4. Sep 25, 2006 #3
    no lol

    well i have to use the quadratic formula?
  5. Sep 25, 2006 #4
    Yes, and all the roots are complex. Are you sure you don't see how to factor that? I'll rewrite it this way:

    [tex]x^2(x^2 + 4x + 13) + x^2 + (4x + 13) = 0[/tex]
  6. Sep 25, 2006 #5
    i thought u were trying to lead me to grouping them to factor but doesn't look like that....

  7. Sep 25, 2006 #6
    Hey Data take a look :


  8. Sep 25, 2006 #7
    looks good :smile:
  9. Sep 25, 2006 #8
    <3 you :!!)
  10. Oct 4, 2006 #9
    in matlab:

    >>p= x^4+4x^3+14x^2+4x+13;

    its very easy...heheh
  11. Oct 4, 2006 #10


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    Yes, relying on the previous work of intelligent people is always the easiest way.
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