# Polynomials math homework

1. Sep 25, 2006

### thomasrules

What are the ROots:

x^4+4x^3+14x^2=-4x-13

ok the 13 really causes a problem because you can't factor that.
So I move the right side to the left and then you can't find a number that fits so that it equals zero so I tried factoring it somehow but can't do it can someone help?

2. Sep 25, 2006

### Data

That's a fairly evil problem to give you, but oh well (if I needed to solve it, I'd just throw it into maple and not think about it!).

It's written that way for a reason. Factor the left side and rearrange to change it to

$$x^2(x^2 + 4x + 14) + (4x + 13) = 0.$$

Do you see how to factor it now?

3. Sep 25, 2006

### thomasrules

no lol

well i have to use the quadratic formula?

4. Sep 25, 2006

### Data

Yes, and all the roots are complex. Are you sure you don't see how to factor that? I'll rewrite it this way:

$$x^2(x^2 + 4x + 13) + x^2 + (4x + 13) = 0$$

5. Sep 25, 2006

### thomasrules

i thought u were trying to lead me to grouping them to factor but doesn't look like that....

NEVER MIND HOLD ON IM RETARDED

6. Sep 25, 2006

### thomasrules

Hey Data take a look :

$$(x^2+1)(x^2+4x+13)$$

??????????

7. Sep 25, 2006

### Data

looks good

8. Sep 25, 2006

<3 you :!!)

9. Oct 4, 2006

### access_084

in matlab:

>>p= x^4+4x^3+14x^2+4x+13;
>>roots(p)

its very easy...heheh

10. Oct 4, 2006

### arildno

Yes, relying on the previous work of intelligent people is always the easiest way.