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Pool Ball Momentum Question
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[QUOTE="Kennedy111, post: 4405297, member: 432381"] That was litterally all of the information they gave to me. In the answer though they have: m1v1 + m2v2 = m1v1` + m2v2` (170g)(3.13m/s) + 0 = (170g)(-0.147 m/s) + (155g)(v2') v2' = 3.59 m/s I really just have no idea where they got the -0.147 m/s [/QUOTE]
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