# Popluation Growth

1. Nov 9, 2009

### xpack

I have this
Code (Text):
delete s275x05.txt; diary s275x05.txt
clear; clc; close all; echo on
%
% Stewart 275/05
%
year=[0:1]; % n+1 = year + 50
pop=[728 906];
p=polyfit(year,log(pop),2)
plot(year,pop,'o','MarkerFaceColor','r')
hold on
x=[0:0.01:6];
y=exp(polyval(p,x));
plot(x,y)
hold on
%part a
%popluation at year 1900
x1900=3
%
echo off; diary off
What I am stuck at is how do I say I want the y value when x = 3?

2. Nov 10, 2009

### willeh

i just got finished with that problem, and mine is a little bit different than yours. for instance, on the polyfit lines, you don't need to make them quadratic, i just made mine linear. also, i didn't do parts a b and c because on the website (http://calclab.math.tamu.edu/~dmanuel/calclab/m151/Fall/2009c_matlab8.html) all it says is to use exponential fitting on the pairs of points. so it's a lot simpler than you're making it out to be. all in all, i got this:

'delete s275x05.txt; diary s275x05.txt
clear; clc; close all; echo on

year=[0:1];
pop=[728 906];
p=polyfit(year,log(pop),1)
plot(year,pop,'o','MarkerFaceColor','r')
hold on
x=[0:0.01:6];
y=exp(polyval(p,x));
plot(x,y)
hold off

year=[2:3];
pop=[1171 1608]
p=polyfit(year,log(pop),1)
plot(year,pop,'o','MarkerFaceColor','r')
hold on
x=[0:0.01:6];
y=exp(polyval(p,x));
plot(x,y)
hold off

year=[3:4];
pop=[1608 2517];
p=polyfit(year,log(pop),1)
plot(year,pop,'o','MarkerFaceColor','r')
hold on
x=[0:0.01:6];
y=exp(polyval(p,x));
plot(x,y)
hold off

year=[0:4];
pop=[728 906 1171 1608 2517];
p=polyfit(year,log(pop),1)
plot(year,pop,'o','MarkerFaceColor','r')
hold on
x=[0:0.01:6];
y=exp(polyval(p,x));
plot(x,y)
hold off

echo off; diary off'