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Porjectile motion question

  1. Jan 29, 2017 #1
    1. The problem statement, all variables and given/known data
    A shell is fired from a cliff that is 36m above a horizontal plane. the muzzle speed of the shell is 80.0m/s and it is fired at an elevation of 25 degrees above the horizontal. a) show that thetime of flight is 7.84 seconds.

    2. Relevant equations
    dy = viy(t) + 0.5(a)(t2)

    3. The attempt at a solution
    i got yp to
    0 = 0.5(-9.8)(t2) + (80sin25)(t) - (36)

    now, i know that i msut use the quadratic eq. but why is that -36m wrong in the equation, in my corrections it says it should be a positive 36 and be a -36 when it is on the left side of the equation. How do i know when to make the vertical displacement negative?
     
  2. jcsd
  3. Jan 29, 2017 #2
    -36 is correct, but it looks like you put it on the wrong side of the equation.

    The displacement and the acceleration and velocities have to be in agreement with each other.
     
  4. Jan 29, 2017 #3
    sorry for the confusion, i meant that i already moved the 36 from the left side to the right side making it -36, however that is apparently not correct, as it is -36 from the left side to begin with then becomes positive on the right side. why is that?
     
  5. Jan 29, 2017 #4
    The terms have to be in agreement with each other. In other words, the initial velocity is in the opposite direction of the acceleration and displacement. So if you are calling acceleration negative, then the displacement has to be negative and the initial velocity has to be positive. Of course, you could reverse all of them if you wanted to.
     
  6. Jan 29, 2017 #5

    gneill

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    Staff: Mentor

    It's up to you to choose your coordinate system before writing your equations. If you set the origin at the launch point with y increasing upwards then the final elevation (when the shell hits the ground below the cliff) will be negative. If you choose y increasing downwards then the change in elevation is positive, but you then need to change the signs of the velocity and acceleration to accommodate the choice of axes direction. If you choose the ground level for y = 0 then you need to incorporate the initial elevation (height of the cliff) into your equation.
     
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