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Position and acceleration

  1. Apr 15, 2017 #1
    1. The problem statement, all variables and given/known data
    All numerical constants are in the appropriate units, so that R (t) in units of meters, and a = 3.1 sec-1.

    What is acceleration size (in meters per second ^ 2) t = 1 / 1.1 sec?

    Note: When calculating sin (at), make sure the computer is in radian mode.

    2. Relevant equations
    R(t)= 8.4sin(at) +(3.1e^(-7t)) +6.9t^3

    3. The attempt at a solution
    Couldn't get to a solution
     
  2. jcsd
  3. Apr 15, 2017 #2

    Nidum

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    Please try to explain this problem more clearly . Post the complete original wording of the problem as given to you if possible
     
  4. Apr 15, 2017 #3
    f6f98a3e2f7c3be31b34ca42ea2ba476.png

    R (t) in meters and a= 3.1 sec^-1

    What is its acceleration (m/s^2) in t = 1 / 1.1 seconds?
     
  5. Apr 15, 2017 #4

    haruspex

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    How do you go from an expression for position to one for acceleration?
    Do you mean literally ##\frac {1}{1.1}## seconds? That is a very odd way to specify the time.
     
    Last edited: Apr 15, 2017
  6. Apr 15, 2017 #5
    ok. but this is data in question.
     
  7. Apr 15, 2017 #6

    haruspex

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    Ok, so answer my first question.
     
  8. Apr 15, 2017 #7
    Have to cut twice the equation and put t
     
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