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Position given ax vx &t

  1. Sep 8, 2008 #1
    1. The problem statement, all variables and given/known data
    [​IMG]
    xi=2.0
    ti=0

    i know the acceleration is -2.0 @ t=3 using the change v/ change t (rise over run)
    the vx@ t=3 is two
    and t=3
    so i need to find the position of x
    so i pluged in the formula x= xi+vt+1/2vt2 and I get 11..but i'm way off

    2. Relevant equations

    see above

    3. The attempt at a solution

    tried a few times working from going from the initial x all the way and I get 11 again.

    Am I not entering in the sig figs right or am i way off?

    I just found this forum and love it!
     
  2. jcsd
  3. Sep 8, 2008 #2

    Redbelly98

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    Staff Emeritus
    Science Advisor
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    That equation is for constant acceleration only.
    The acceleration changes in this problem, so that equation will not work.

    How do you get displacement from velocity in general?
     
  4. Sep 8, 2008 #3

    i figured it out
    I wasn't using the right vi

    got me on the right path thanks!!
     
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