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## Homework Statement

Two particles 1 and 2, each carrying 6.0 nC of charge, are located along an x axis, one particle atx=−30 mm and the other at x = 30 mm. Where along the y axis is a particle 3 carrying a charge of +2.0 nC if it experiences an electric force of 6.9 × 10^−5 N ȷ^?

## Homework Equations

Coulomb's law: F = (k*q1*q2)/d^2

Pythagorean Theorm: c = SQRT((a^2) + b^2))

## The Attempt at a Solution

So I know the answer is 10mm and 40mm. However, throughout my work, I am not even close to said values. Here is the work I have done:

Some notes on my progress:

1.) I first began by finding Fx (since Fy was defined in the problem as 6.9x10^-5, and was split since I only need the force of a single 6.0 nC charge).

2.) After calculating this value, I took both force vectors and added them together to obtain the final total Force between particle 1 or 2 and particle 3.

3.) Taking this force value, I plugged it back into Coulomb's law in an attempt to obtain the value of d (In this problem, x = 30mm, y is what I am trying to find. So by finding d, I can use Pythagorean to calculate it). However... this is where things break apart. When I find d, I realize that this value is SMALLER than my x value... which makes 0 sense. From here I became absolutely lost.

https://scontent.fewr1-2.fna.fbcdn.net/v/t34.0-12/14237562_1253883344636041_2264484480519635381_n.jpg?oh=5f8d0bafacc2fd1b915de0e148810ab5&oe=57D91A9E

https://scontent.fewr1-2.fna.fbcdn.net/v/t34.0-12/14330114_1253883357969373_2960711846063879329_n.jpg?oh=a12feff8c85bc3b70ac88aebe43c94cb&oe=57D84E03

If someone could guide me from this point, I would greatly appreciate it! Thank you!