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Position of a particle

  1. Apr 7, 2007 #1
    1. The problem statement, all variables and given/known data
    The position of a particle is given by the function x = ( 8t^3 - 3t^2 + 5) m, where t is in s.
    (a) At what time or times does vx = 0 m/s?

    (b) What are the particle's position and acceleration at t1?

    What are the particle's position and acceleration at t2?

    2. Relevant equations
    v1 = v0 + at
    x1 = x0 + v0 + (1/2)at^2
    vx = dx/dt
    a = dv/dt


    3. The attempt at a solution
    Quite honestly, I'm not sure where to begin with this problem. If someone could help me to start it that would be greatly appreciated, thanks!
     
  2. jcsd
  3. Apr 7, 2007 #2

    hage567

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    You know that v = dx/dt, and a = dv/dt. So for starters, take the derivatives.
     
  4. Apr 7, 2007 #3

    mjsd

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    these are equation for constant acceleration. for your case acceleration is time dependent so can't use these
     
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