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Position of a particle

  • Thread starter spin360
  • Start date
  • #1
13
0

Homework Statement


The position of a particle is given by the function x = ( 8t^3 - 3t^2 + 5) m, where t is in s.
(a) At what time or times does vx = 0 m/s?

(b) What are the particle's position and acceleration at t1?

What are the particle's position and acceleration at t2?

Homework Equations


v1 = v0 + at
x1 = x0 + v0 + (1/2)at^2
vx = dx/dt
a = dv/dt


The Attempt at a Solution


Quite honestly, I'm not sure where to begin with this problem. If someone could help me to start it that would be greatly appreciated, thanks!
 

Answers and Replies

  • #2
hage567
Homework Helper
1,509
2
You know that v = dx/dt, and a = dv/dt. So for starters, take the derivatives.
 
  • #3
mjsd
Homework Helper
726
3
1.
v1 = v0 + at
x1 = x0 + v0 + (1/2)at^2



these are equation for constant acceleration. for your case acceleration is time dependent so can't use these
 

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