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Position Vector

  1. Jul 2, 2013 #1
    How do you formulate the Position Vector:

    x^m = [t____x____y____z]

    x^m = [f(t)____ax/2*t^2 + vx*t + x0____ay/2*t^2 + vy*t + y0____az/2*t^2 + vz*t + z0]

    dx^m / dt = [df(t) / dt____ax*t + vx____ay*t + vy____az*t + vz]

    What do you put in the"t" position "f(t)".
     
    Last edited: Jul 2, 2013
  2. jcsd
  3. Jul 2, 2013 #2

    tiny-tim

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    Hi Philosophaie! :smile:

    Perhaps I'm misunderstanding you, but shouldn't that be …

    x^a = [t____ax/2*t^2 + vx*t + x0____ay/2*t^2 + vy*t + y0____az/2*t^2 + vz*t + z0]

    dx^a / dt = [1____ax*t + vx____ay*t + vy____az*t + vz] ? :confused:
     
  4. Jul 2, 2013 #3
    I am basing my Metric Tensor on:


    [tex]g_{ik}*\frac{dx^{i}}{dt}*\frac{dx^{k}}{dt} = -1[/tex]


    Do I have the right equation for being in a gravitational field say near a Black Hole with nothing else around?

    I am trying to develop a general realistic Metric Tensor that has the acceleration, velocity and position all in a gravitational field (with GR rather than Newtonian).
     
    Last edited: Jul 2, 2013
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