(adsbygoogle = window.adsbygoogle || []).push({}); A positively charged oil drop is injected into a region of uniform electric field between two oppositely charged, horizontally oriented plates. If the electric force on the drop is found to be 8.60 × 10−16 N and the electric field magnitude is 153 V/m, what is the magnitude of the charge on the drop in terms of the elementary charge e?

The correct answer should be 35e, but I am not getting it.

My attempt:

I tried the equation

F = Eq

8.60 × 10−16 N = (153 V/m)(q)

q = 5.6 x 10-18 N

Then I used

e = q/k

e = 5.6 x 10-18 N / 8.99 x 10^9

which does not give me the right answer

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# Homework Help: Positively charged oil drop

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