# Possibilities Maths

1. Jan 1, 2014

### Hepic

To bring odd number with a die,is 50%.
If I play with the die two times,how possibilities I have to bring odd number?

2. Jan 1, 2014

### Jilang

There would be a 25% chance of getting two odd numbers, 25% chance of two even numbers and a 50% chance of getting one of each. So the probability of getting at least one odd number would be 75%.

3. Jan 1, 2014

### Hepic

Yea,I am talking about bringing at least one time "odds".
How we find the 75%?

4. Jan 1, 2014

### Jilang

Well you can write out all 36 combinations and add them up. Or you can think of it as 100% less the probabability of getting both even which is 100% - 50%x50% = 100%-25%=75%

5. Jan 1, 2014

### Hepic

So If I undestood good,If I play "3" times,for the same result,I have 83,3333%.

Right?

6. Jan 1, 2014

### HallsofIvy

Staff Emeritus
No, apparently you didn't understand at all. The probability of getting all three even is $(1/2)^3= 1/8= 0.125$ so the probability of "at least one head in three rolls" is $1- 0.125= 0.875$.