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Possible Distance question

  1. Mar 18, 2014 #1

    a.k

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    1. The problem statement, all variables and given/known data
    Two joggers are approaching a water fountain from opposite directions. Jogger A begins 3.0 miles west of the water fountain, with a constant velocity of 4.0 mph due east. Jogger B begins 2.0 miles east of the water fountain, with a constant velocity of 3.0 mph due west. How far are the joggers from the water fountain when they meet one another?


    2. Relevant equations
    t=d/v

    3. The attempt at a solution

    xa=3 miles west @ 4mph
    xb=2 miles @ 3 mph

    t=5/7

    I need some guidance as to what I should do now.
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Mar 18, 2014 #2

    tiny-tim

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    hi a.k! :wink:
    fine so far! :smile:

    you've found that, with a relative speed of 7 mph, and a distance of 5 miles, the time taken to reduce the distance to 0 is 5/7 hour

    sooo … starting at either end (it makes no difference), at what point will they meet? :wink:
     
  4. Mar 18, 2014 #3

    a.k

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    I still don't understand.
     
  5. Mar 18, 2014 #4

    tiny-tim

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    do you mean you didn't understand this bit? :confused:
     
  6. Mar 18, 2014 #5

    a.k

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    Unfortunately so.

    I am curious if this is correct:

    5/7*4mph and 5/7*3mph

    20/7 and 15/7

    2.86 and 2.14 miles

    2.86-2.14= 0.14 miles west of the fountain

    I think I got this by a fluke by using d=tv then subtracted the mileage.
     
  7. Mar 18, 2014 #6

    tiny-tim

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    yes this is correct

    21/7 miles minus 20/7 miles = 1/7 miles west

    14/7 miles minus 15/7 miles = minus 1/7 miles east = 1/7 miles west

    either way you get 1/7 miles west :smile:

    i don't understand what you're not getting about this :confused:
     
  8. Mar 18, 2014 #7

    a.k

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    I don't know either tiny tim.

    I am happy I was able to figure it out though.
     
  9. Mar 18, 2014 #8
    Basically, your total distance is 2 + 3 miles = 5 miles, and speed is 4 - (-3) = 7 mph. You have distance, speed and time. Surely you know the equation that makes it all work.

    Anyways, your most recent work looks fine.
     
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