# Possible Distance question

1. Mar 18, 2014

### a.k

1. The problem statement, all variables and given/known data
Two joggers are approaching a water fountain from opposite directions. Jogger A begins 3.0 miles west of the water fountain, with a constant velocity of 4.0 mph due east. Jogger B begins 2.0 miles east of the water fountain, with a constant velocity of 3.0 mph due west. How far are the joggers from the water fountain when they meet one another?

2. Relevant equations
t=d/v

3. The attempt at a solution

xa=3 miles west @ 4mph
xb=2 miles @ 3 mph

t=5/7

I need some guidance as to what I should do now.
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

2. Mar 18, 2014

### tiny-tim

hi a.k!
fine so far!

you've found that, with a relative speed of 7 mph, and a distance of 5 miles, the time taken to reduce the distance to 0 is 5/7 hour

sooo … starting at either end (it makes no difference), at what point will they meet?

3. Mar 18, 2014

### a.k

I still don't understand.

4. Mar 18, 2014

### tiny-tim

do you mean you didn't understand this bit?

5. Mar 18, 2014

### a.k

Unfortunately so.

I am curious if this is correct:

5/7*4mph and 5/7*3mph

20/7 and 15/7

2.86 and 2.14 miles

2.86-2.14= 0.14 miles west of the fountain

I think I got this by a fluke by using d=tv then subtracted the mileage.

6. Mar 18, 2014

### tiny-tim

yes this is correct

21/7 miles minus 20/7 miles = 1/7 miles west

14/7 miles minus 15/7 miles = minus 1/7 miles east = 1/7 miles west

either way you get 1/7 miles west

7. Mar 18, 2014

### a.k

I don't know either tiny tim.

I am happy I was able to figure it out though.

8. Mar 18, 2014

### majormaaz

Basically, your total distance is 2 + 3 miles = 5 miles, and speed is 4 - (-3) = 7 mph. You have distance, speed and time. Surely you know the equation that makes it all work.

Anyways, your most recent work looks fine.