 Problem Statement
 Consider the oddodd nucleus 38Cl , which has 17 protons and 21 neutrons. Its 17th proton sits in the 1d[SUB]3/2[/SUB] orbit, while its 21st neutron is in the 1f[SUB]7/2[/SUB] orbital. Calculate the possible spins and parities of this nucleus.
 Relevant Equations

I = total nuclear spin
j = angular momentum of a single nucleon
s = spin of a single nucleon
l = orbital angular momentum
π = parity
I = j[SUB]1[/SUB]  j[SUB]2[/SUB] trough j[SUB]1[/SUB] + j[SUB]2[/SUB]
π = (1)[SUP]l[/SUP]
I'm actually not even 100% sure about the formulas, as in my book they explain j, s and l quite unclearly. Could anyone give me a proper explanation as how to see these and if i'm using them correctly.
What i tried to do was determine the proton and neutron angular momentum, spin and parity.
As the proton is in the 1d_{3/2}, l = 2, j = 3/2, s = +1/2 and π = (1)^{2} = +
The neutron is in the 1f_{7/2}, l = 3, j = 7/2, s = 1/2 and π = (1)^{3} = 
The possible nuclear spin levels would be 1, 2, 3, 4, 5
The possible nuclear spins would all have parity (1)(+1) = 
So the possible spins and parities would then be 1^{}, 2^{}, 3^{}, 4^{}, 5^{}
What i tried to do was determine the proton and neutron angular momentum, spin and parity.
As the proton is in the 1d_{3/2}, l = 2, j = 3/2, s = +1/2 and π = (1)^{2} = +
The neutron is in the 1f_{7/2}, l = 3, j = 7/2, s = 1/2 and π = (1)^{3} = 
The possible nuclear spin levels would be 1, 2, 3, 4, 5
The possible nuclear spins would all have parity (1)(+1) = 
So the possible spins and parities would then be 1^{}, 2^{}, 3^{}, 4^{}, 5^{}