# Possible spins and parities of an odd-odd nucleus

#### JeroenL

Problem Statement
Consider the odd-odd nucleus 38Cl , which has 17 protons and 21 neutrons. Its 17th proton sits in the 1d[SUB]3/2[/SUB] orbit, while its 21st neutron is in the 1f[SUB]7/2[/SUB] orbital. Calculate the possible spins and parities of this nucleus.
Relevant Equations
I = total nuclear spin
j = angular momentum of a single nucleon
s = spin of a single nucleon
l = orbital angular momentum
π = parity

I = |j[SUB]1[/SUB] - j[SUB]2[/SUB]| trough j[SUB]1[/SUB] + j[SUB]2[/SUB]
π = (-1)[SUP]l[/SUP]
I'm actually not even 100% sure about the formulas, as in my book they explain j, s and l quite unclearly. Could anyone give me a proper explanation as how to see these and if i'm using them correctly.

What i tried to do was determine the proton and neutron angular momentum, spin and parity.
As the proton is in the 1d3/2, l = 2, j = 3/2, s = +1/2 and π = (-1)2 = +
The neutron is in the 1f7/2, l = 3, j = 7/2, s = -1/2 and π = (-1)3 = -

The possible nuclear spin levels would be 1, 2, 3, 4, 5
The possible nuclear spins would all have parity (-1)(+1) = -

So the possible spins and parities would then be 1-, 2-, 3-, 4-, 5-

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