Hi, Sorry to bring this up again but I've been looking so long for an answer to a new question that arrised. This is how I see it and tried to explain it, so plz correct me if I'm wrong. example 01: 1 bulb in a simple circuit : 12v , bulb 01 : 2ohm expln: potential energy drops by 12 v over bulb; Ok np so far. example 02: 2 bulbs in series: 12v , bulb 01 : 2 ohm , 8v bulb 02 : 1 ohm , 4v But here's my problem: THE DIFFERENCE IN V. (POTENTIAL DROP) OVER BULB 01 IN EXAMPLE 01(12v.) AND BULB 02 IN EXAMPLE 02(8V). Which one is the right explaination? EXPLAINATION 01: The energy needed per electron to pass through bulb's 01 ions is still the same so each electron loses the same energy per coulomb but there are less passing so the drop in energy is less over bulb 01. Since there are less q/s(I)(more energy to spend per electron) every electron starts with more energy (more then with just one light bulb)so it also can get past bulb 02. But this is a bit in contradiction (to my textbook) with the fact that the potential drop is said to be 8v per coulomb on bulb 01, so the [del]E/q, the drop per electron(loss in energy to go through bulb 01), in bulb 01 is in my above explaination still 12v but since there are less electron the v-meter measures less namely 8v. EXPLAINATION 02: The energy needed to pass through light bulb 01 IS less then in example 01 because I is smaller and therefore there is less energy loss in the same bulb(bulb 01) for some sort of atomic reason I don't get(maybe because the electrons are moving less fast)?