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Potenetial Differences

  1. Feb 8, 2009 #1
    1. The problem statement, all variables and given/known data
    The capacitors in the Figure are initially uncharged and are connected, as in the diagram, with switch S open. The applied potential difference is V_ab = + 210V

    What is the potential difference V_ad after switch S is closed?

    2. Relevant equations
    Q=C_eq*V
    V_ab=Q/C

    3. The attempt at a solution
    I really have no idea how to get started doing this problem. The first part of the problem asked "What is the potential difference V_cd?" This I found easy but once you close the switch I'm not sure how to approach the problem. Specifically how do you go about combining the capacitors to get a C_eq. Thanks for any help.
     

    Attached Files:

  2. jcsd
  3. Feb 9, 2009 #2

    tiny-tim

    User Avatar
    Science Advisor
    Homework Helper

    Hi Black Armadillo! :smile:

    Hint: the potential at c and d is the same, so draw the diagram again without the line cd, with the points c and d the same. :wink:
     
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