# Potential and dipole moment

1. Feb 29, 2012

### leopold123

Could anyone help me with the following problem???
Ammonia molecule has a dipole moment of 1.47D. Calculate the potential generated by this molecule at a point on a dipole axis at a distance of 52.0 nm from the centre of the dipole. how large will the potential be if an ion of charge q=1e=1.6*10^-19 C is brought at this point? it would be really helpful if you provide any required useful explanation...thank you...waiitng eagerly for ur response...

2. Feb 29, 2012

### leopold123

$V = \frac{1}{4 \pi \epsilon} \frac{2 p}{r^2}$ where p is the dipole moment which according to the problem is given to be 1.47 D.