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Potential and electric field

  1. May 12, 2013 #1
    The electric potential V at any point (x,y,z) in space is given by V=4(x^2) volts (all in meters). The electric field at the point (1m,0m,2m) is?

    -->
    dV= - (E.dr),
    magnitude of r =sqrt(5),
    V at the point will be 4, which => 4=-*integration sign*E.dr
    how to solve this?
     
  2. jcsd
  3. May 12, 2013 #2

    ehild

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    Do it backwards. The electric field is equal to the negative gradient of the potential. Do you know what "gradient" is?

    ehild
     
  4. May 12, 2013 #3
    Definitely :P Thanks.
     
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