- #1
lincsimp
- 7
- 0
Homework Statement
Why is a potential divider required in a sensor circuit?
Homework Equations
V_out = r1/(r1+r2)*V_in
The Attempt at a Solution
Firstly you can get the required voltage across the sensor by changing the resistance of r2 (if r1 is the sensor).
Apparently, though, using a potential divider also increases the sensitivity of the sensor. ie. a small change in resistance causes a larger change in output, but I don't see how this works. could someone explain?
Thanks