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A 0.240 kg block on a vertical spring with a spring constant of 5e3 N/m is pushed downward, compressing the spring 0.080 m. When released, the block leaves the spring and travels upward vertically. How high does it rise above the point of release?

I know that PE= 1/2 kx^2

so I got .5 x 5e3 x .08^2=16 I'm not sure where the mass comes into this equation. I also know that you have to subtract your anser from the point of release so i tried 16-.08 but it didn't work...

Thank-you