A .4 kg mass moves up 40 cm along an incline. The vertical height of the incline is 7.0 cm. The potential energy change is??(adsbygoogle = window.adsbygoogle || []).push({});

I used the formula for PEC. 1/2k(deltaX)^2 which got me to 320 joules. That is wrong though. What am i doing wrong???

If a force of .85N pulled parallel up along the surface of the incline is required to raise the mass back to the top of the incline, how much work is done?

i used W=fd

w=.85(40)

w=34

but that answer is wrong. Im doing something wrong.

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# Homework Help: Potential Energy Change

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