Potential energy graph x-component

  • Thread starter psingh
  • Start date
  • #1
18
0
What is the x-component of the force on the particle at x=5, 15, 25, and 35 cm

i thought it was just the slope?!? but im wrong ,some help?

x=15 i know F=0
 

Attachments

  • graph.jpg
    graph.jpg
    10.5 KB · Views: 915

Answers and Replies

  • #2
429
0
psingh said:
What is the x-component of the force on the particle at x=5, 15, 25, and 35 cm

i thought it was just the slope?!? but im wrong ,some help?

x=15 i know F=0


so close!

there's a formula that should be in your text:

|F| = - dU/dx. (direction is along the x-axis.)

(if, like in this problem, we are only concerned with one dimension.)

in three dimensions, F = - grad U
 
  • #3
18
0
oye you're right neg. slope =] thankss
 
  • #4
538
2
In differential form , the relation is fiven by

[itex]F = \frac{-dU}{dR}[/itex]

Just find the slope of the tangents at each of the given x-coordinates . The answer will be positive or negative depending on whether Potential is decreasing or increasing at that point.

BJ
 
Last edited:

Related Threads on Potential energy graph x-component

  • Last Post
Replies
15
Views
21K
  • Last Post
Replies
3
Views
2K
  • Last Post
Replies
3
Views
6K
  • Last Post
Replies
1
Views
1K
Replies
3
Views
7K
  • Last Post
Replies
3
Views
29K
  • Last Post
Replies
3
Views
3K
  • Last Post
Replies
1
Views
46K
  • Last Post
Replies
9
Views
17K
Replies
4
Views
25K
Top