- #1
Yuravian
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Homework Statement
A 0.40-kg particle moves under the influence of a single conservative force. At point A where the particle has a speed of 10 m/s, the potential energy associated with the conservative force is +40 J. As the particle moves from A to B, the force does +25 J of work on the particle. What is the value of the potential energy at point B?
The problem, for me is that there is no diagram included on the homework sent out in the email from the professor and I think the proper problem would have had a diagram of the path. I may be wrong though.
Homework Equations
Well, this is clearly a work and kinetic energy problem, so:
[tex]W=\Delta U+\Delta K[/tex]
[tex]W=Fdcos\theta[/tex] (not sure if it applies here)
[tex]\Delta K=1/2mv^{2}_{o}-1/2mv^{2}_{f}[/tex]
[tex]\Delta U=mgh_{o}-mgh_{f}[/tex] (again, I don't think this applies)
The Attempt at a Solution
straighten out my variables:
[tex]v_o=10 m/s[/tex]
[tex]K_o=1/2mv^2_o=20 J[/tex]
[tex]U_o=40 J[/tex]
[tex]W=25 J=U_f-U_o+K_f-K_o[/tex]
So at this point, I do not have the acceleration of the particle (cannot find F or v final), and no information on the final state of the particle other than the amount of work done on it. Where should I go from here?